4x^2-20x+10x+50=0

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Solution for 4x^2-20x+10x+50=0 equation:



4x^2-20x+10x+50=0
We add all the numbers together, and all the variables
4x^2-10x+50=0
a = 4; b = -10; c = +50;
Δ = b2-4ac
Δ = -102-4·4·50
Δ = -700
Delta is less than zero, so there is no solution for the equation

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